∫cosx esinx dx\int \cos x\, e^{\sin x}\,dx
∫2ax+bax2+bx+c dx(a≠0)\int \frac{2ax+b}{ax^2+bx+c}\,dx \quad(a\neq 0)
∫cosx (1+sin2x) dx\int \cos x\,(1+\sin^2 x)\,dx
∫cosx cos5(sinx) dx\int \cos x\;\cos^{5}(\sin x)\,dx
∫dxxlnx(x>0, x≠1)\int \frac{dx}{x\ln x} \qquad(x>0,\ x\neq 1)
∫x1+x2 dx\int \frac{x}{1+x^2}\,dx
∫x 1+x2 dx\int \frac{x}{\sqrt{\,1+x^2\,}}\,dx
∫ex1+ex dx\int \frac{e^{x}}{1+e^{x}}\,dx
∫cosx a+sinx dx(a∈R)\int \frac{\cos x}{\,a+\sin x\,}\,dx \quad(a\in\mathbb{R})
∫kx+m(kx+m)2+c dx(k≠0)\int \frac{kx+m}{(kx+m)^2+c}\,dx \quad(k\neq 0)
∫λ (2ax+b)ax2+bx+c dx(a≠0)\int \frac{\lambda\,(2ax+b)}{ax^2+bx+c}\,dx \quad(a\neq 0)
∫(3x+1) e(3x+1)2 dx\int (3x+1)\,e^{(3x+1)^2}\,dx
∫0π/2cosx1+sinx dx\int_{0}^{\pi/2}\frac{\cos x}{1+\sin x}\,dx
∫lnxx dx(x>0)\int \frac{\ln x}{x}\,dx \qquad(x>0)
1) Let u=sinxu=\sin x, du=cosx dxdu=\cos x\,dx.
∫cosx esinx dx=∫eu du=eu+C=esinx+C.\int \cos x\,e^{\sin x}\,dx=\int e^{u}\,du=e^{u}+C=e^{\sin x}+C.
2) Let u=ax2+bx+cu=ax^2+bx+c, du=(2ax+b) dxdu=(2ax+b)\,dx.
∫2ax+bax2+bx+c dx=∫duu=ln∣u∣+C=ln∣ax2+bx+c∣+C.\int \frac{2ax+b}{ax^2+bx+c}\,dx=\int \frac{du}{u}=\ln|u|+C=\ln|ax^2+bx+c|+C.
3) Let u=sinxu=\sin x, du=cosx dxdu=\cos x\,dx.
∫cosx(1+sin2x) dx=∫(1+u2) du=u+u33+C=sinx+sin3x3+C.\int \cos x(1+\sin^2 x)\,dx=\int (1+u^2)\,du=u+\tfrac{u^3}{3}+C =\sin x+\tfrac{\sin^3 x}{3}+C.
4) Let u=sinxu=\sin x, du=cosx dxdu=\cos x\,dx.
∫cosx cos5(sinx) dx=∫cos5u du=∫cos4u cosu du.\int \cos x\,\cos^{5}(\sin x)\,dx=\int \cos^{5}u\,du =\int \cos^{4}u\;\cos u\,du.
Write cos4u=(1−sin2u)2\cos^{4}u=(1-\sin^{2}u)^2. Let w=sinuw=\sin u, dw=cosu dudw=\cos u\,du:
∫(1−w2)2 dw=w−23w3+15w5+C.\int (1-w^{2})^{2}\,dw =w-\tfrac{2}{3}w^{3}+\tfrac{1}{5}w^{5}+C.
Back-substitute w=sinu, u=sinxw=\sin u,\ u=\sin x:
sin(sinx)−23sin3(sinx)+15sin5(sinx)+C.\sin(\sin x)-\tfrac{2}{3}\sin^{3}(\sin x)+\tfrac{1}{5}\sin^{5}(\sin x)+C.
5) Let u=lnxu=\ln x, du=dxxdu=\frac{dx}{x}.
∫dxxlnx=∫duu=ln∣u∣+C=ln∣lnx∣+C.\int \frac{dx}{x\ln x}=\int \frac{du}{u}=\ln|u|+C=\ln|\ln x|+C.
6) Let u=1+x2u=1+x^2, du=2x dxdu=2x\,dx.
∫x1+x2 dx=12∫duu=12ln(1+x2)+C.\int \frac{x}{1+x^2}\,dx=\tfrac12\int \frac{du}{u} =\tfrac12\ln(1+x^2)+C.
7) Let u=1+x2u=1+x^2, du=2x dxdu=2x\,dx.
∫x1+x2 dx=12∫u−1/2 du=1+x2+C.\int \frac{x}{\sqrt{1+x^2}}\,dx=\tfrac12\int u^{-1/2}\,du =\sqrt{1+x^2}+C.
8) Let u=1+exu=1+e^{x}, du=ex dxdu=e^{x}\,dx.
∫ex1+ex dx=∫duu=ln(1+ex)+C.\int \frac{e^{x}}{1+e^{x}}\,dx=\int \frac{du}{u}=\ln(1+e^{x})+C.
9) Let u=a+sinxu=a+\sin x, du=cosx dxdu=\cos x\,dx.
∫cosxa+sinx dx=∫duu=ln∣a+sinx∣+C.\int \frac{\cos x}{a+\sin x}\,dx=\int \frac{du}{u}=\ln|a+\sin x|+C.
10) Let u=(kx+m)2+cu=(kx+m)^2+c. Then du=2(kx+m)k dx⇒(kx+m) dx=du2kdu=2(kx+m)k\,dx\Rightarrow (kx+m)\,dx=\dfrac{du}{2k}.
∫kx+m(kx+m)2+c dx=12k∫duu=12kln ((kx+m)2+c)+C.\int \frac{kx+m}{(kx+m)^2+c}\,dx =\frac{1}{2k}\int \frac{du}{u} =\frac{1}{2k}\ln\!\big((kx+m)^2+c\big)+C.
11) Let u=ax2+bx+cu=ax^2+bx+c, du=(2ax+b) dxdu=(2ax+b)\,dx.
∫λ (2ax+b)ax2+bx+c dx=λ∫duu=λln∣ax2+bx+c∣+C.\int \frac{\lambda\,(2ax+b)}{ax^2+bx+c}\,dx =\lambda\int \frac{du}{u} =\lambda\ln|ax^2+bx+c|+C.
12) Let u=(3x+1)2u=(3x+1)^2, du=6(3x+1) dx⇒(3x+1) dx=du6du=6(3x+1)\,dx\Rightarrow (3x+1)\,dx=\tfrac{du}{6}.
∫(3x+1)e(3x+1)2 dx=16∫eu du=16e(3x+1)2+C.\int (3x+1)e^{(3x+1)^2}\,dx=\tfrac16\int e^{u}\,du =\tfrac16 e^{(3x+1)^2}+C.
13) Let u=1+sinxu=1+\sin x, du=cosx dxdu=\cos x\,dx.
∫0π/2cosx1+sinx dx=∫u=1u=2duu=ln2.\int_{0}^{\pi/2}\frac{\cos x}{1+\sin x}\,dx =\int_{u=1}^{u=2}\frac{du}{u} =\ln 2.
14) Let u=lnxu=\ln x, du=dxxdu=\frac{dx}{x}.
∫lnxx dx=∫u du=12(lnx)2+C.\int \frac{\ln x}{x}\,dx=\int u\,du=\tfrac12(\ln x)^2+C.
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