U-Substitution Practice Problems

Questions

  1.  

cosxesinxdx\int \cos x\, e^{\sin x}\,dx

  1.  

2ax+bax2+bx+cdx(a0)\int \frac{2ax+b}{ax^2+bx+c}\,dx \quad(a\neq 0)

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cosx(1+sin2x)dx\int \cos x\,(1+\sin^2 x)\,dx

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cosx  cos5(sinx)dx\int \cos x\;\cos^{5}(\sin x)\,dx

  1.  

dxxlnx(x>0, x1)\int \frac{dx}{x\ln x} \qquad(x>0,\ x\neq 1)

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x1+x2dx\int \frac{x}{1+x^2}\,dx

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x1+x2dx\int \frac{x}{\sqrt{\,1+x^2\,}}\,dx

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ex1+exdx\int \frac{e^{x}}{1+e^{x}}\,dx

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cosxa+sinxdx(aR)\int \frac{\cos x}{\,a+\sin x\,}\,dx \quad(a\in\mathbb{R})

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kx+m(kx+m)2+cdx(k0)\int \frac{kx+m}{(kx+m)^2+c}\,dx \quad(k\neq 0)

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λ(2ax+b)ax2+bx+cdx(a0)\int \frac{\lambda\,(2ax+b)}{ax^2+bx+c}\,dx \quad(a\neq 0)

  1.  

(3x+1)e(3x+1)2dx\int (3x+1)\,e^{(3x+1)^2}\,dx

  1.  

0π/2cosx1+sinxdx\int_{0}^{\pi/2}\frac{\cos x}{1+\sin x}\,dx

  1.  

lnxxdx(x>0)\int \frac{\ln x}{x}\,dx \qquad(x>0)

 

Solutions

1) Let u=sinxu=\sin x, du=cosxdxdu=\cos x\,dx.

cosxesinxdx=eudu=eu+C=esinx+C.\int \cos x\,e^{\sin x}\,dx=\int e^{u}\,du=e^{u}+C=e^{\sin x}+C.

2) Let u=ax2+bx+cu=ax^2+bx+c, du=(2ax+b)dxdu=(2ax+b)\,dx.

2ax+bax2+bx+cdx=duu=lnu+C=lnax2+bx+c+C.\int \frac{2ax+b}{ax^2+bx+c}\,dx=\int \frac{du}{u}=\ln|u|+C=\ln|ax^2+bx+c|+C.

3) Let u=sinxu=\sin x, du=cosxdxdu=\cos x\,dx.

cosx(1+sin2x)dx=(1+u2)du=u+u33+C=sinx+sin3x3+C.\int \cos x(1+\sin^2 x)\,dx=\int (1+u^2)\,du=u+\tfrac{u^3}{3}+C =\sin x+\tfrac{\sin^3 x}{3}+C.

4) Let u=sinxu=\sin x, du=cosxdxdu=\cos x\,dx.

cosxcos5(sinx)dx=cos5udu=cos4u  cosudu.\int \cos x\,\cos^{5}(\sin x)\,dx=\int \cos^{5}u\,du =\int \cos^{4}u\;\cos u\,du.

Write cos4u=(1sin2u)2\cos^{4}u=(1-\sin^{2}u)^2. Let w=sinuw=\sin u, dw=cosududw=\cos u\,du:

(1w2)2dw=w23w3+15w5+C.\int (1-w^{2})^{2}\,dw =w-\tfrac{2}{3}w^{3}+\tfrac{1}{5}w^{5}+C.

Back-substitute w=sinu, u=sinxw=\sin u,\ u=\sin x:

sin(sinx)23sin3(sinx)+15sin5(sinx)+C.\sin(\sin x)-\tfrac{2}{3}\sin^{3}(\sin x)+\tfrac{1}{5}\sin^{5}(\sin x)+C.

5) Let u=lnxu=\ln x, du=dxxdu=\frac{dx}{x}.

dxxlnx=duu=lnu+C=lnlnx+C.\int \frac{dx}{x\ln x}=\int \frac{du}{u}=\ln|u|+C=\ln|\ln x|+C.

6) Let u=1+x2u=1+x^2, du=2xdxdu=2x\,dx.

x1+x2dx=12duu=12ln(1+x2)+C.\int \frac{x}{1+x^2}\,dx=\tfrac12\int \frac{du}{u} =\tfrac12\ln(1+x^2)+C.

7) Let u=1+x2u=1+x^2, du=2xdxdu=2x\,dx.

x1+x2dx=12u1/2du=1+x2+C.\int \frac{x}{\sqrt{1+x^2}}\,dx=\tfrac12\int u^{-1/2}\,du =\sqrt{1+x^2}+C.

8) Let u=1+exu=1+e^{x}, du=exdxdu=e^{x}\,dx.

ex1+exdx=duu=ln(1+ex)+C.\int \frac{e^{x}}{1+e^{x}}\,dx=\int \frac{du}{u}=\ln(1+e^{x})+C.

9) Let u=a+sinxu=a+\sin x, du=cosxdxdu=\cos x\,dx.

cosxa+sinxdx=duu=lna+sinx+C.\int \frac{\cos x}{a+\sin x}\,dx=\int \frac{du}{u}=\ln|a+\sin x|+C.

10) Let u=(kx+m)2+cu=(kx+m)^2+c. Then du=2(kx+m)kdx(kx+m)dx=du2kdu=2(kx+m)k\,dx\Rightarrow (kx+m)\,dx=\dfrac{du}{2k}.

kx+m(kx+m)2+cdx=12kduu=12kln ⁣((kx+m)2+c)+C.\int \frac{kx+m}{(kx+m)^2+c}\,dx =\frac{1}{2k}\int \frac{du}{u} =\frac{1}{2k}\ln\!\big((kx+m)^2+c\big)+C.

11) Let u=ax2+bx+cu=ax^2+bx+c, du=(2ax+b)dxdu=(2ax+b)\,dx.

λ(2ax+b)ax2+bx+cdx=λduu=λlnax2+bx+c+C.\int \frac{\lambda\,(2ax+b)}{ax^2+bx+c}\,dx =\lambda\int \frac{du}{u} =\lambda\ln|ax^2+bx+c|+C.

12) Let u=(3x+1)2u=(3x+1)^2, du=6(3x+1)dx(3x+1)dx=du6du=6(3x+1)\,dx\Rightarrow (3x+1)\,dx=\tfrac{du}{6}.

(3x+1)e(3x+1)2dx=16eudu=16e(3x+1)2+C.\int (3x+1)e^{(3x+1)^2}\,dx=\tfrac16\int e^{u}\,du =\tfrac16 e^{(3x+1)^2}+C.

13) Let u=1+sinxu=1+\sin x, du=cosxdxdu=\cos x\,dx.

0π/2cosx1+sinxdx=u=1u=2duu=ln2.\int_{0}^{\pi/2}\frac{\cos x}{1+\sin x}\,dx =\int_{u=1}^{u=2}\frac{du}{u} =\ln 2.

14) Let u=lnxu=\ln x, du=dxxdu=\frac{dx}{x}.

lnxxdx=udu=12(lnx)2+C.\int \frac{\ln x}{x}\,dx=\int u\,du=\tfrac12(\ln x)^2+C.

 

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