ddx(e)= ?\frac{d}{dx}(e)=\ ?
ddx ∫01x dx= ?\frac{d}{dx}\,\int_{0}^{1} x\,dx=\ ?
cos ( ddx∫abf(x) dx)= ?\cos\!\Big(\,\frac{d}{dx}\int_{a}^{b} f(x)\,dx\Big)=\ ?
ddx ∫01x dt= ?\frac{d}{dx}\,\int_{0}^{1} x\,dt=\ ?
1) ee is a constant, not exe^{x}.
ddx(e)=0.\frac{d}{dx}(e)=0.
2) A definite integral with fixed bounds is a constant.
∫01x dx=12⇒ddx(12)=0.\int_{0}^{1} x\,dx=\tfrac12 \quad\Rightarrow\quad \frac{d}{dx}(\tfrac12)=0.
3) Inside the cosine, ddx∫abf(x) dx=0\dfrac{d}{dx}\int_{a}^{b} f(x)\,dx=0.
cos(0)=1.\cos(0)=1.
4) Here the integral is with respect to tt, so xx is a constant during the integration.
∫01x dt=x ∫01dt=x⇒ddx(x)=1.\int_{0}^{1} x\,dt = x\!\int_{0}^{1} dt = x \quad\Rightarrow\quad \frac{d}{dx}(x)=1.
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