Consider the reaction in glycolysis, catalyzed by the enzyme enolase.

a) Propose a reasonable mechanism for this enzymatic reaction, assuming it occurs in more than one step. Use B to denote a generic basic residue in the enzyme (don’t worry about specifics). What type of elimination is occurring here?

b) Enolase uses Mg2+ ions. What might be a possible role of these Mg2+ ions with reference to your mechanism from part a? 

c) Why is OH protonated as it leaves in the mechanism from part a? 

d) Draw a mechanism for the reverse reaction. What type of reaction is occurring here?










Solution

a) E1cB is the type of elimination



b) The Mg2+ stabilizes the negatively charged intermediate (see mechanism in part a)


c) OH- is a bad leaving group (strong base; unstable). Therefore, it is protonated while leaving so that it leaves as H2O, which is a good (stable) leaving group.


d) 1,4-addition (i.e. conjugate addition)

Leave a Reply

Discover more from MathSciProblems

Subscribe now to keep reading and get access to the full archive.

Continue reading